Solve 5+3*1/2-3=3(1/2)-(8*1/2-6

$$5+3 \times \frac{ 1 }{ 2 } -3 = 3( \frac{ 1 }{ 2 } )-(8 \times \frac{ 1 }{ 2 } -6$$

Verify

Solution Steps

Multiply 3 and \frac{1}{2} to get \frac{3}{2}.

$$5+\frac{3}{2}-3=3\times \frac{1}{2}-\left(8\times \frac{1}{2}-6\right)$$

Convert 5 to fraction \frac{10}{2}.

$$\frac{10}{2}+\frac{3}{2}-3=3\times \frac{1}{2}-\left(8\times \frac{1}{2}-6\right)$$

Since \frac{10}{2} and \frac{3}{2} have the same denominator, add them by adding their numerators.

$$\frac{10+3}{2}-3=3\times \frac{1}{2}-\left(8\times \frac{1}{2}-6\right)$$

Add 10 and 3 to get 13.

$$\frac{13}{2}-3=3\times \frac{1}{2}-\left(8\times \frac{1}{2}-6\right)$$

Convert 3 to fraction \frac{6}{2}.

$$\frac{13}{2}-\frac{6}{2}=3\times \frac{1}{2}-\left(8\times \frac{1}{2}-6\right)$$

Since \frac{13}{2} and \frac{6}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{13-6}{2}=3\times \frac{1}{2}-\left(8\times \frac{1}{2}-6\right)$$

Subtract 6 from 13 to get 7.

$$\frac{7}{2}=3\times \frac{1}{2}-\left(8\times \frac{1}{2}-6\right)$$

Multiply 3 and \frac{1}{2} to get \frac{3}{2}.

$$\frac{7}{2}=\frac{3}{2}-\left(8\times \frac{1}{2}-6\right)$$

Multiply 8 and \frac{1}{2} to get \frac{8}{2}.

$$\frac{7}{2}=\frac{3}{2}-\left(\frac{8}{2}-6\right)$$

Divide 8 by 2 to get 4.

$$\frac{7}{2}=\frac{3}{2}-\left(4-6\right)$$

Subtract 6 from 4 to get -2.

$$\frac{7}{2}=\frac{3}{2}-\left(-2\right)$$

The opposite of -2 is 2.

$$\frac{7}{2}=\frac{3}{2}+2$$

Convert 2 to fraction \frac{4}{2}.

$$\frac{7}{2}=\frac{3}{2}+\frac{4}{2}$$

Since \frac{3}{2} and \frac{4}{2} have the same denominator, add them by adding their numerators.

$$\frac{7}{2}=\frac{3+4}{2}$$

Add 3 and 4 to get 7.

$$\frac{7}{2}=\frac{7}{2}$$

Compare \frac{7}{2} and \frac{7}{2}.

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