Factor
5\left(z-2\right)\left(z^{2}+2z+4\right)
Evaluate
5\left(z^{3}-8\right)
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5\left(z^{3}-8\right)
Factor out 5.
\left(z-2\right)\left(z^{2}+2z+4\right)
Consider z^{3}-8. Rewrite z^{3}-8 as z^{3}-2^{3}. The difference of cubes can be factored using the rule: a^{3}-b^{3}=\left(a-b\right)\left(a^{2}+ab+b^{2}\right).
5\left(z-2\right)\left(z^{2}+2z+4\right)
Rewrite the complete factored expression. Polynomial z^{2}+2z+4 is not factored since it does not have any rational roots.
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