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5z^{2}=10
Add 10 to both sides. Anything plus zero gives itself.
z^{2}=\frac{10}{5}
Divide both sides by 5.
z^{2}=2
Divide 10 by 5 to get 2.
z=\sqrt{2} z=-\sqrt{2}
Take the square root of both sides of the equation.
5z^{2}-10=0
Quadratic equations like this one, with an x^{2} term but no x term, can still be solved using the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, once they are put in standard form: ax^{2}+bx+c=0.
z=\frac{0±\sqrt{0^{2}-4\times 5\left(-10\right)}}{2\times 5}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 5 for a, 0 for b, and -10 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
z=\frac{0±\sqrt{-4\times 5\left(-10\right)}}{2\times 5}
Square 0.
z=\frac{0±\sqrt{-20\left(-10\right)}}{2\times 5}
Multiply -4 times 5.
z=\frac{0±\sqrt{200}}{2\times 5}
Multiply -20 times -10.
z=\frac{0±10\sqrt{2}}{2\times 5}
Take the square root of 200.
z=\frac{0±10\sqrt{2}}{10}
Multiply 2 times 5.
z=\sqrt{2}
Now solve the equation z=\frac{0±10\sqrt{2}}{10} when ± is plus.
z=-\sqrt{2}
Now solve the equation z=\frac{0±10\sqrt{2}}{10} when ± is minus.
z=\sqrt{2} z=-\sqrt{2}
The equation is now solved.