Factor
5\left(y+4\right)\left(y^{2}-4y+16\right)
Evaluate
5\left(y^{3}+64\right)
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5\left(y^{3}+64\right)
Factor out 5.
\left(y+4\right)\left(y^{2}-4y+16\right)
Consider y^{3}+64. Rewrite y^{3}+64 as y^{3}+4^{3}. The sum of cubes can be factored using the rule: a^{3}+b^{3}=\left(a+b\right)\left(a^{2}-ab+b^{2}\right).
5\left(y+4\right)\left(y^{2}-4y+16\right)
Rewrite the complete factored expression. Polynomial y^{2}-4y+16 is not factored since it does not have any rational roots.
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