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5\left(xy^{2}-5xy+6x\right)
Factor out 5.
x\left(y^{2}-5y+6\right)
Consider xy^{2}-5xy+6x. Factor out x.
a+b=-5 ab=1\times 6=6
Consider y^{2}-5y+6. Factor the expression by grouping. First, the expression needs to be rewritten as y^{2}+ay+by+6. To find a and b, set up a system to be solved.
-1,-6 -2,-3
Since ab is positive, a and b have the same sign. Since a+b is negative, a and b are both negative. List all such integer pairs that give product 6.
-1-6=-7 -2-3=-5
Calculate the sum for each pair.
a=-3 b=-2
The solution is the pair that gives sum -5.
\left(y^{2}-3y\right)+\left(-2y+6\right)
Rewrite y^{2}-5y+6 as \left(y^{2}-3y\right)+\left(-2y+6\right).
y\left(y-3\right)-2\left(y-3\right)
Factor out y in the first and -2 in the second group.
\left(y-3\right)\left(y-2\right)
Factor out common term y-3 by using distributive property.
5x\left(y-3\right)\left(y-2\right)
Rewrite the complete factored expression.