Solve for x
x=\frac{8y+3}{5}
Solve for y
y=\frac{5x-3}{8}
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5x=3+8y
Add 8y to both sides.
5x=8y+3
The equation is in standard form.
\frac{5x}{5}=\frac{8y+3}{5}
Divide both sides by 5.
x=\frac{8y+3}{5}
Dividing by 5 undoes the multiplication by 5.
-8y=3-5x
Subtract 5x from both sides.
\frac{-8y}{-8}=\frac{3-5x}{-8}
Divide both sides by -8.
y=\frac{3-5x}{-8}
Dividing by -8 undoes the multiplication by -8.
y=\frac{5x-3}{8}
Divide 3-5x by -8.
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Limits
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