Solve for x
x\leq \frac{5}{2}
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5x-8+x\leq 7
Add x to both sides.
6x-8\leq 7
Combine 5x and x to get 6x.
6x\leq 7+8
Add 8 to both sides.
6x\leq 15
Add 7 and 8 to get 15.
x\leq \frac{15}{6}
Divide both sides by 6. Since 6 is positive, the inequality direction remains the same.
x\leq \frac{5}{2}
Reduce the fraction \frac{15}{6} to lowest terms by extracting and canceling out 3.
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