Solve for x
x=\frac{3iy}{5}+\left(-7+\frac{21}{5}i\right)
Solve for y
y=-\frac{5ix}{3}+\left(-7-\frac{35}{3}i\right)
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5x-3iy=-35+21i
Multiply 3 and i to get 3i.
5x=-35+21i+3iy
Add 3iy to both sides.
5x=3iy+\left(-35+21i\right)
The equation is in standard form.
\frac{5x}{5}=\frac{3iy+\left(-35+21i\right)}{5}
Divide both sides by 5.
x=\frac{3iy+\left(-35+21i\right)}{5}
Dividing by 5 undoes the multiplication by 5.
x=\frac{3iy}{5}+\left(-7+\frac{21}{5}i\right)
Divide -35+21i+3iy by 5.
5x-3iy=-35+21i
Multiply 3 and i to get 3i.
-3iy=-35+21i-5x
Subtract 5x from both sides.
\frac{-3iy}{-3i}=\frac{-35+21i-5x}{-3i}
Divide both sides by -3i.
y=\frac{-35+21i-5x}{-3i}
Dividing by -3i undoes the multiplication by -3i.
y=-\frac{5ix}{3}+\left(-7-\frac{35}{3}i\right)
Divide -35+21i-5x by -3i.
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