Solve for x
x=\frac{2\left(y+20\right)}{5}
Solve for y
y=\frac{5\left(x-8\right)}{2}
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5x=40+2y
Add 2y to both sides.
5x=2y+40
The equation is in standard form.
\frac{5x}{5}=\frac{2y+40}{5}
Divide both sides by 5.
x=\frac{2y+40}{5}
Dividing by 5 undoes the multiplication by 5.
x=\frac{2y}{5}+8
Divide 40+2y by 5.
-2y=40-5x
Subtract 5x from both sides.
\frac{-2y}{-2}=\frac{40-5x}{-2}
Divide both sides by -2.
y=\frac{40-5x}{-2}
Dividing by -2 undoes the multiplication by -2.
y=\frac{5x}{2}-20
Divide 40-5x by -2.
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