Solve for x
x>\frac{65}{3}
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5x-30-\left(-x\right)>100
To find the opposite of 30-x, find the opposite of each term.
5x-30+x>100
The opposite of -x is x.
6x-30>100
Combine 5x and x to get 6x.
6x>100+30
Add 30 to both sides.
6x>130
Add 100 and 30 to get 130.
x>\frac{130}{6}
Divide both sides by 6. Since 6 is positive, the inequality direction remains the same.
x>\frac{65}{3}
Reduce the fraction \frac{130}{6} to lowest terms by extracting and canceling out 2.
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