Solve for x
x>\frac{20}{23}
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25x-5>2x+15
Multiply both sides of the equation by 5. Since 5 is positive, the inequality direction remains the same.
25x-5-2x>15
Subtract 2x from both sides.
23x-5>15
Combine 25x and -2x to get 23x.
23x>15+5
Add 5 to both sides.
23x>20
Add 15 and 5 to get 20.
x>\frac{20}{23}
Divide both sides by 23. Since 23 is positive, the inequality direction remains the same.
Examples
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{ x } ^ { 2 } - 4 x - 5 = 0
Trigonometry
4 \sin \theta \cos \theta = 2 \sin \theta
Linear equation
y = 3x + 4
Arithmetic
699 * 533
Matrix
\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Limits
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}