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5x^{2}=45
Multiply x and x to get x^{2}.
x^{2}=\frac{45}{5}
Divide both sides by 5.
x^{2}=9
Divide 45 by 5 to get 9.
x=3 x=-3
Take the square root of both sides of the equation.
5x^{2}=45
Multiply x and x to get x^{2}.
5x^{2}-45=0
Subtract 45 from both sides.
x=\frac{0±\sqrt{0^{2}-4\times 5\left(-45\right)}}{2\times 5}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 5 for a, 0 for b, and -45 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\times 5\left(-45\right)}}{2\times 5}
Square 0.
x=\frac{0±\sqrt{-20\left(-45\right)}}{2\times 5}
Multiply -4 times 5.
x=\frac{0±\sqrt{900}}{2\times 5}
Multiply -20 times -45.
x=\frac{0±30}{2\times 5}
Take the square root of 900.
x=\frac{0±30}{10}
Multiply 2 times 5.
x=3
Now solve the equation x=\frac{0±30}{10} when ± is plus. Divide 30 by 10.
x=-3
Now solve the equation x=\frac{0±30}{10} when ± is minus. Divide -30 by 10.
x=3 x=-3
The equation is now solved.