Solve 5x*5x=25

$$5 x \times 5 x = 25$$

Solve for x

$$x=1$$

$$x=-1$$

Steps by Finding Square Root

Multiply x and x to get x^{2}.

$$5x^{2}\times 5=25$$

Multiply 5 and 5 to get 25.

$$25x^{2}=25$$

Divide both sides by 25.

$$x^{2}=\frac{25}{25}$$

Divide 25 by 25 to get 1.

$$x^{2}=1$$

Take the square root of both sides of the equation.

$$x=1 x=-1$$

Steps Using the Quadratic Formula

Multiply x and x to get x^{2}.

$$5x^{2}\times 5=25$$

Multiply 5 and 5 to get 25.

$$25x^{2}=25$$

Subtract 25 from both sides.

$$25x^{2}-25=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 25 for a, 0 for b, and -25 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times 25\left(-25\right)}}{2\times 25}$$

Square 0.

$$x=\frac{0±\sqrt{-4\times 25\left(-25\right)}}{2\times 25}$$

Multiply -4 times 25.

$$x=\frac{0±\sqrt{-100\left(-25\right)}}{2\times 25}$$

Multiply -100 times -25.

$$x=\frac{0±\sqrt{2500}}{2\times 25}$$

Take the square root of 2500.

$$x=\frac{0±50}{2\times 25}$$

Multiply 2 times 25.

$$x=\frac{0±50}{50}$$

Now solve the equation x=\frac{0±50}{50} when ± is plus. Divide 50 by 50.

$$x=1$$

Now solve the equation x=\frac{0±50}{50} when ± is minus. Divide -50 by 50.

$$x=-1$$

The equation is now solved.

$$x=1 x=-1$$