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5\left(x^{2}y+2xy-6x^{3}y\right)
Factor out 5.
xy\left(x+2-6x^{2}\right)
Consider x^{2}y+2xy-6x^{3}y. Factor out xy.
-6x^{2}+x+2
Consider x+2-6x^{2}. Rearrange the polynomial to put it in standard form. Place the terms in order from highest to lowest power.
a+b=1 ab=-6\times 2=-12
Factor the expression by grouping. First, the expression needs to be rewritten as -6x^{2}+ax+bx+2. To find a and b, set up a system to be solved.
-1,12 -2,6 -3,4
Since ab is negative, a and b have the opposite signs. Since a+b is positive, the positive number has greater absolute value than the negative. List all such integer pairs that give product -12.
-1+12=11 -2+6=4 -3+4=1
Calculate the sum for each pair.
a=4 b=-3
The solution is the pair that gives sum 1.
\left(-6x^{2}+4x\right)+\left(-3x+2\right)
Rewrite -6x^{2}+x+2 as \left(-6x^{2}+4x\right)+\left(-3x+2\right).
2x\left(-3x+2\right)-3x+2
Factor out 2x in -6x^{2}+4x.
\left(-3x+2\right)\left(2x+1\right)
Factor out common term -3x+2 by using distributive property.
5xy\left(-3x+2\right)\left(2x+1\right)
Rewrite the complete factored expression.