Solve 5x^2-3y=4-2x

$$5 x ^ { 2 } - 3 y = 4 - 2 x$$

Solve for y

$$y=\frac{5x^{2}+2x-4}{3}$$

Steps for Solving Linear Equation

Subtract 5x^{2} from both sides.

$$-3y=4-2x-5x^{2}$$

Divide both sides by -3.

$$\frac{-3y}{-3}=\frac{4-2x-5x^{2}}{-3}$$

Dividing by -3 undoes the multiplication by -3.

$$y=\frac{4-2x-5x^{2}}{-3}$$

Divide 4-2x-5x^{2} by -3.

$$y=\frac{5x^{2}+2x-4}{3}$$

Solve for x (complex solution)

$$x=\frac{\sqrt{15y+21}-1}{5}$$

$$x=\frac{-\sqrt{15y+21}-1}{5}$$

Solve for x

$$x=\frac{\sqrt{15y+21}-1}{5}$$

$$x=\frac{-\sqrt{15y+21}-1}{5}\text{, }y\geq -\frac{7}{5}$$