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5x^{2}=6+1
Add 1 to both sides.
5x^{2}=7
Add 6 and 1 to get 7.
x^{2}=\frac{7}{5}
Divide both sides by 5.
x=\frac{\sqrt{35}}{5} x=-\frac{\sqrt{35}}{5}
Take the square root of both sides of the equation.
5x^{2}-1-6=0
Subtract 6 from both sides.
5x^{2}-7=0
Subtract 6 from -1 to get -7.
x=\frac{0±\sqrt{0^{2}-4\times 5\left(-7\right)}}{2\times 5}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 5 for a, 0 for b, and -7 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\times 5\left(-7\right)}}{2\times 5}
Square 0.
x=\frac{0±\sqrt{-20\left(-7\right)}}{2\times 5}
Multiply -4 times 5.
x=\frac{0±\sqrt{140}}{2\times 5}
Multiply -20 times -7.
x=\frac{0±2\sqrt{35}}{2\times 5}
Take the square root of 140.
x=\frac{0±2\sqrt{35}}{10}
Multiply 2 times 5.
x=\frac{\sqrt{35}}{5}
Now solve the equation x=\frac{0±2\sqrt{35}}{10} when ± is plus.
x=-\frac{\sqrt{35}}{5}
Now solve the equation x=\frac{0±2\sqrt{35}}{10} when ± is minus.
x=\frac{\sqrt{35}}{5} x=-\frac{\sqrt{35}}{5}
The equation is now solved.