Solve 5x^2+mx-12=0

$$5 x ^ { 2 } + m x - 12 = 0$$

Solve for m

$$m=-5x+\frac{12}{x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Subtract 5x^{2} from both sides. Anything subtracted from zero gives its negation.

$$mx-12=-5x^{2}$$

Add 12 to both sides.

$$mx=-5x^{2}+12$$

The equation is in standard form.

$$xm=12-5x^{2}$$

Divide both sides by x.

$$\frac{xm}{x}=\frac{12-5x^{2}}{x}$$

Dividing by x undoes the multiplication by x.

$$m=\frac{12-5x^{2}}{x}$$

Divide -5x^{2}+12 by x.

$$m=-5x+\frac{12}{x}$$

Solve for x

$$x=\frac{\sqrt{m^{2}+240}-m}{10}$$

$$x=\frac{-\sqrt{m^{2}+240}-m}{10}$$