Solve for b
b=-5x+\frac{1}{x}
x\neq 0
Solve for x
x=\frac{\sqrt{b^{2}+20}-b}{10}
x=\frac{-\sqrt{b^{2}+20}-b}{10}
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bx=1-5x^{2}
Subtract 5x^{2} from both sides.
xb=1-5x^{2}
The equation is in standard form.
\frac{xb}{x}=\frac{1-5x^{2}}{x}
Divide both sides by x.
b=\frac{1-5x^{2}}{x}
Dividing by x undoes the multiplication by x.
b=-5x+\frac{1}{x}
Divide 1-5x^{2} by x.
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