Solve 5x^2+3y+23=1

$$5 x ^ { 2 } + 3 y + 23 = 1$$

Solve for y

$$y=\frac{-5x^{2}-22}{3}$$

Steps for Solving Linear Equation

Subtract 5x^{2} from both sides.

$$3y+23=1-5x^{2}$$

Subtract 23 from both sides.

$$3y=1-5x^{2}-23$$

Subtract 23 from 1 to get -22.

$$3y=-22-5x^{2}$$

The equation is in standard form.

$$3y=-5x^{2}-22$$

Divide both sides by 3.

$$\frac{3y}{3}=\frac{-5x^{2}-22}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$y=\frac{-5x^{2}-22}{3}$$

Solve for x (complex solution)

$$x=-\frac{\sqrt{-15y-110}}{5}$$

$$x=\frac{\sqrt{-15y-110}}{5}$$

Solve for x

$$x=\frac{\sqrt{-15y-110}}{5}$$

$$x=-\frac{\sqrt{-15y-110}}{5}\text{, }y\leq -\frac{22}{3}$$