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Solve for x (complex solution)
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5x^{2}=-25
Subtract 25 from both sides. Anything subtracted from zero gives its negation.
x^{2}=\frac{-25}{5}
Divide both sides by 5.
x^{2}=-5
Divide -25 by 5 to get -5.
x=\sqrt{5}i x=-\sqrt{5}i
The equation is now solved.
5x^{2}+25=0
Quadratic equations like this one, with an x^{2} term but no x term, can still be solved using the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, once they are put in standard form: ax^{2}+bx+c=0.
x=\frac{0±\sqrt{0^{2}-4\times 5\times 25}}{2\times 5}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 5 for a, 0 for b, and 25 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\times 5\times 25}}{2\times 5}
Square 0.
x=\frac{0±\sqrt{-20\times 25}}{2\times 5}
Multiply -4 times 5.
x=\frac{0±\sqrt{-500}}{2\times 5}
Multiply -20 times 25.
x=\frac{0±10\sqrt{5}i}{2\times 5}
Take the square root of -500.
x=\frac{0±10\sqrt{5}i}{10}
Multiply 2 times 5.
x=\sqrt{5}i
Now solve the equation x=\frac{0±10\sqrt{5}i}{10} when ± is plus.
x=-\sqrt{5}i
Now solve the equation x=\frac{0±10\sqrt{5}i}{10} when ± is minus.
x=\sqrt{5}i x=-\sqrt{5}i
The equation is now solved.