Solve 5x^2+2x^2-20-8=0

$$5 x ^ { 2 } + 2 x ^ { 2 } - 20 - 8 = 0$$

Solve for x

$$x=2$$

$$x=-2$$

Steps Using Difference of Squares

Combine 5x^{2} and 2x^{2} to get 7x^{2}.

$$7x^{2}-20-8=0$$

Subtract 8 from -20 to get -28.

$$7x^{2}-28=0$$

Divide both sides by 7.

$$x^{2}-4=0$$

Consider x^{2}-4. Rewrite x^{2}-4 as x^{2}-2^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(x-2\right)\left(x+2\right)=0$$

To find equation solutions, solve x-2=0 and x+2=0.

$$x=2 x=-2$$

Steps by Finding Square Root

Combine 5x^{2} and 2x^{2} to get 7x^{2}.

$$7x^{2}-20-8=0$$

Subtract 8 from -20 to get -28.

$$7x^{2}-28=0$$

Add 28 to both sides. Anything plus zero gives itself.

$$7x^{2}=28$$

Divide both sides by 7.

$$x^{2}=\frac{28}{7}$$

Divide 28 by 7 to get 4.

$$x^{2}=4$$

Take the square root of both sides of the equation.

$$x=2 x=-2$$

Steps Using the Quadratic Formula

Combine 5x^{2} and 2x^{2} to get 7x^{2}.

$$7x^{2}-20-8=0$$

Subtract 8 from -20 to get -28.

$$7x^{2}-28=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 7 for a, 0 for b, and -28 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times 7\left(-28\right)}}{2\times 7}$$

Square 0.

$$x=\frac{0±\sqrt{-4\times 7\left(-28\right)}}{2\times 7}$$

Multiply -4 times 7.

$$x=\frac{0±\sqrt{-28\left(-28\right)}}{2\times 7}$$

Multiply -28 times -28.

$$x=\frac{0±\sqrt{784}}{2\times 7}$$

Take the square root of 784.

$$x=\frac{0±28}{2\times 7}$$

Multiply 2 times 7.

$$x=\frac{0±28}{14}$$

Now solve the equation x=\frac{0±28}{14} when ± is plus. Divide 28 by 14.

$$x=2$$

Now solve the equation x=\frac{0±28}{14} when ± is minus. Divide -28 by 14.

$$x=-2$$

The equation is now solved.

$$x=2 x=-2$$