Solve 5x^frac{7{2}}+6x^frac{3{2}} | Microsoft Math Solver

Factor

x^{\frac{3}{2}}\left(5x^{2}+6\right)

Solution Steps

5 x ^ { \frac { 7 } { 2 } } + 6 x ^ { \frac { 3 } { 2 } }

Factor out x^{\frac{3}{2}}. Polynomial 5x^{2}+6 is not factored since it does not have any rational roots.

x^{\frac{3}{2}}\left(5x^{2}+6\right)

Evaluate

x^{\frac{3}{2}}\left(5x^{2}+6\right)

Graph

Quiz

Algebra

5 x ^ { \frac { 7 } { 2 } } + 6 x ^ { \frac { 3 } { 2 } }

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How do you multiply \displaystyle{\left({3}{x}^{{{\frac{{{7}}}{{{2}}}}}}\right)}^{{{6}}}{\left({x}^{{{2}}}\right)}^{{{6}}} ?

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See the entire multiplication process below: Explanation: First, use these rules of exponents to begin the multiplication process: \displaystyle{\left({x}^{{{a}}}\right)}^{{{b}}}={x}^{{{\left({a}\right)}\times{\left({b}\right)}}} ...

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\displaystyle{x}={258} Explanation: \displaystyle{\left({x}-{2}\right)}^{{\frac{{3}}{{4}}}}=\frac{{{386}-{2}}}{{6}} \displaystyle{\left({x}-{2}\right)}^{{\frac{{3}}{{4}}}}={64} \displaystyle{\left({x}-{2}\right)}^{{{\left(\frac{{3}}{{4}}\right)}{\left(\frac{{4}}{{3}}\right)}}}={64}^{{\frac{{4}}{{3}}}} ...

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https://www.tiger-algebra.com/drill/(x~3-18x-8)/(x-4)/

(x3-18x-8)/(x-4) Final result : (x2 - 4x - 2) • (x + 4) ——————————————————————— x - 4 See results of polynomial long division: 1. In step #01.04 Step by step solution : Step 1 : x3 - 18x - 8 ...

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See explanation. Explanation:

How do you divide \displaystyle\frac{{{2}{x}^{{3}}+{15}{x}+{12}}}{{{x}+{1}}} using polynomial long division?

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\displaystyle{2}{x}^{{2}}-{2}{x}+{17}-\frac{{5}}{{{x}+{1}}} with remainder \displaystyle{\left(-{5}\right)} (see Explanation for polynomial long division) Explanation: \displaystyle{\left.{\left(,,{\left({2}{x}^{{2}}\right)},{\left(-{2}{x}\right)},{\left(+{17}\right)},\right)},{\left(,,\text{----},\text{------},\text{------},\text{-----}\right)},{\left({x}+{1},\text{)},{2}{x}^{{3}},,+{15}{x},+{12}\right)},{\left(,,{2}{x}^{{3}},+{2}{x}^{{2}},,\right)},{\left(,,\text{----},\text{------},,\right)},{\left(,,,-{2}{x}^{{2}},+{15}{x},\right)},{\left(,,,-{2}{x}^{{2}},{\left(\text{X}\right)}-{2}{x},\right)},{\left(,,,\text{------},\text{-------},\right)},{\left(,,,,{\left(\text{X}\right)}{17}{x},{\left(\text{X}\right)}{12}\right)},{\left(,,,,{\left(\text{X}\right)}{17}{x},+{17}\right)},{\left(,,,,\text{-------},\text{------}\right)},{\left(,,,,,{\left(-{5}\right)}\right)}\right.}

How do you divide \displaystyle\frac{{\left(-{15}{x}\right)}^{{7}}}{{\left({25}{x}\right)}^{{9}}} ?

https://socratic.org/questions/how-do-you-divide-15x-7-25x-9

There are probably many ways to express this result; my version is \displaystyle{\left(\text{XXXX}\right)} \displaystyle-\frac{{3}^{{7}}}{{{5}^{{5}}{x}^{{2}}}} Explanation: \displaystyle\frac{{{\left(-{15}{x}\right)}^{{7}}}}{{{\left({25}{x}\right)}^{{9}}}} ...

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x^{\frac{3}{2}}\left(5x^{2}+6\right)

Factor out x^{\frac{3}{2}}. Polynomial 5x^{2}+6 is not factored since it does not have any rational roots.

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