Solve for x
x=\frac{±\frac{\sqrt{21}}{7}}{5}
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5x=±\frac{\sqrt{3}}{\sqrt{7}}
Rewrite the square root of the division \sqrt{\frac{3}{7}} as the division of square roots \frac{\sqrt{3}}{\sqrt{7}}.
5x=±\frac{\sqrt{3}\sqrt{7}}{\left(\sqrt{7}\right)^{2}}
Rationalize the denominator of \frac{\sqrt{3}}{\sqrt{7}} by multiplying numerator and denominator by \sqrt{7}.
5x=±\frac{\sqrt{3}\sqrt{7}}{7}
The square of \sqrt{7} is 7.
5x=±\frac{\sqrt{21}}{7}
To multiply \sqrt{3} and \sqrt{7}, multiply the numbers under the square root.
\frac{5x}{5}=\frac{±\frac{\sqrt{21}}{7}}{5}
Divide both sides by 5.
x=\frac{±\frac{\sqrt{21}}{7}}{5}
Dividing by 5 undoes the multiplication by 5.
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