Solve 5x+4*sqrt{9}-2x=1x+sqrt{16}+2^2

$$5 x + 4 \cdot \sqrt { 9 } - 2 x = 1 x + \sqrt { 16 } + 2 ^ { 2 }$$

Solve for x

$$x=-2$$

Steps for Solving Linear Equation

Calculate the square root of 9 and get 3.

$$5x+4\times 3-2x=1x+\sqrt{16}+2^{2}$$

Multiply 4 and 3 to get 12.

$$5x+12-2x=1x+\sqrt{16}+2^{2}$$

Combine 5x and -2x to get 3x.

$$3x+12=1x+\sqrt{16}+2^{2}$$

Calculate the square root of 16 and get 4.

$$3x+12=1x+4+2^{2}$$

Calculate 2 to the power of 2 and get 4.

$$3x+12=1x+4+4$$

Add 4 and 4 to get 8.

$$3x+12=1x+8$$

Subtract 1x from both sides.

$$3x+12-x=8$$

Combine 3x and -x to get 2x.

$$2x+12=8$$

Subtract 12 from both sides.

$$2x=8-12$$

Subtract 12 from 8 to get -4.

$$2x=-4$$

Divide both sides by 2.

$$x=\frac{-4}{2}$$

Divide -4 by 2 to get -2.

$$x=-2$$