Solve for x
x=\frac{8-3y}{5}
Solve for y
y=\frac{8-5x}{3}
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5x-8=-3y
Subtract 3y from both sides. Anything subtracted from zero gives its negation.
5x=-3y+8
Add 8 to both sides.
5x=8-3y
The equation is in standard form.
\frac{5x}{5}=\frac{8-3y}{5}
Divide both sides by 5.
x=\frac{8-3y}{5}
Dividing by 5 undoes the multiplication by 5.
3y-8=-5x
Subtract 5x from both sides. Anything subtracted from zero gives its negation.
3y=-5x+8
Add 8 to both sides.
3y=8-5x
The equation is in standard form.
\frac{3y}{3}=\frac{8-5x}{3}
Divide both sides by 3.
y=\frac{8-5x}{3}
Dividing by 3 undoes the multiplication by 3.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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