Solve 5x+3y+10=3x+5y+4

$$5 x + 3 y + 10 = 3 x + 5 y + 4$$

Solve for x

$$x=y-3$$

Steps for Solving Linear Equation

Subtract 3x from both sides.

$$5x+3y+10-3x=5y+4$$

Combine 5x and -3x to get 2x.

$$2x+3y+10=5y+4$$

Subtract 3y from both sides.

$$2x+10=5y+4-3y$$

Combine 5y and -3y to get 2y.

$$2x+10=2y+4$$

Subtract 10 from both sides.

$$2x=2y+4-10$$

Subtract 10 from 4 to get -6.

$$2x=2y-6$$

Divide both sides by 2.

$$\frac{2x}{2}=\frac{2y-6}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$x=\frac{2y-6}{2}$$

Divide -6+2y by 2.

$$x=y-3$$

Solve for y

$$y=x+3$$

Steps for Solving Linear Equation

Subtract 5y from both sides.

$$5x+3y+10-5y=3x+4$$

Combine 3y and -5y to get -2y.

$$5x-2y+10=3x+4$$

Subtract 5x from both sides.

$$-2y+10=3x+4-5x$$

Combine 3x and -5x to get -2x.

$$-2y+10=-2x+4$$

Subtract 10 from both sides.

$$-2y=-2x+4-10$$

Subtract 10 from 4 to get -6.

$$-2y=-2x-6$$

Divide both sides by -2.

$$\frac{-2y}{-2}=\frac{-2x-6}{-2}$$

Dividing by -2 undoes the multiplication by -2.

$$y=\frac{-2x-6}{-2}$$

Divide -2x-6 by -2.

$$y=x+3$$