Solve for x
x=\frac{48-3z-2y}{5}
Solve for y
y=-\frac{3z}{2}-\frac{5x}{2}+24
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5x+3z=48-2y
Subtract 2y from both sides.
5x=48-2y-3z
Subtract 3z from both sides.
5x=48-3z-2y
The equation is in standard form.
\frac{5x}{5}=\frac{48-3z-2y}{5}
Divide both sides by 5.
x=\frac{48-3z-2y}{5}
Dividing by 5 undoes the multiplication by 5.
2y+3z=48-5x
Subtract 5x from both sides.
2y=48-5x-3z
Subtract 3z from both sides.
2y=48-3z-5x
The equation is in standard form.
\frac{2y}{2}=\frac{48-3z-5x}{2}
Divide both sides by 2.
y=\frac{48-3z-5x}{2}
Dividing by 2 undoes the multiplication by 2.
y=-\frac{3z}{2}-\frac{5x}{2}+24
Divide 48-5x-3z by 2.
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