Solve for x
x\geq 4
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5x+2-8x\leq -10
Subtract 8x from both sides.
-3x+2\leq -10
Combine 5x and -8x to get -3x.
-3x\leq -10-2
Subtract 2 from both sides.
-3x\leq -12
Subtract 2 from -10 to get -12.
x\geq \frac{-12}{-3}
Divide both sides by -3. Since -3 is negative, the inequality direction is changed.
x\geq 4
Divide -12 by -3 to get 4.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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