Solve for x
x=\frac{2y^{2}-z-1}{5}
Solve for y
y=\frac{\sqrt{2\left(5x+z+1\right)}}{2}
y=-\frac{\sqrt{2\left(5x+z+1\right)}}{2}\text{, }x\geq \frac{-z-1}{5}
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5x=2y^{2}-z-1
Subtract 1 from both sides.
\frac{5x}{5}=\frac{2y^{2}-z-1}{5}
Divide both sides by 5.
x=\frac{2y^{2}-z-1}{5}
Dividing by 5 undoes the multiplication by 5.
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Limits
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