Solve 5x+3/2y=12/5

$$5 x + \frac { 3 } { 2 } y = \frac { 12 } { 5 }$$

Solve for x

$$x=-\frac{3y}{10}+\frac{12}{25}$$

Steps for Solving Linear Equation

Subtract \frac{3}{2}y from both sides.

$$5x=\frac{12}{5}-\frac{3}{2}y$$

The equation is in standard form.

$$5x=-\frac{3y}{2}+\frac{12}{5}$$

Divide both sides by 5.

$$\frac{5x}{5}=\frac{-\frac{3y}{2}+\frac{12}{5}}{5}$$

Dividing by 5 undoes the multiplication by 5.

$$x=\frac{-\frac{3y}{2}+\frac{12}{5}}{5}$$

Divide \frac{12}{5}-\frac{3y}{2} by 5.

$$x=-\frac{3y}{10}+\frac{12}{25}$$

Solve for y

$$y=-\frac{10x}{3}+\frac{8}{5}$$

Steps for Solving Linear Equation

Subtract 5x from both sides.

$$\frac{3}{2}y=\frac{12}{5}-5x$$

Divide both sides of the equation by \frac{3}{2}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{3}{2}y}{\frac{3}{2}}=\frac{\frac{12}{5}-5x}{\frac{3}{2}}$$

Dividing by \frac{3}{2} undoes the multiplication by \frac{3}{2}.

$$y=\frac{\frac{12}{5}-5x}{\frac{3}{2}}$$

Divide \frac{12}{5}-5x by \frac{3}{2} by multiplying \frac{12}{5}-5x by the reciprocal of \frac{3}{2}.

$$y=-\frac{10x}{3}+\frac{8}{5}$$