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5x+\frac{3}{2}+\frac{2}{3}x=6
Add \frac{2}{3}x to both sides.
\frac{17}{3}x+\frac{3}{2}=6
Combine 5x and \frac{2}{3}x to get \frac{17}{3}x.
\frac{17}{3}x=6-\frac{3}{2}
Subtract \frac{3}{2} from both sides.
\frac{17}{3}x=\frac{12}{2}-\frac{3}{2}
Convert 6 to fraction \frac{12}{2}.
\frac{17}{3}x=\frac{12-3}{2}
Since \frac{12}{2} and \frac{3}{2} have the same denominator, subtract them by subtracting their numerators.
\frac{17}{3}x=\frac{9}{2}
Subtract 3 from 12 to get 9.
x=\frac{9}{2}\times \frac{3}{17}
Multiply both sides by \frac{3}{17}, the reciprocal of \frac{17}{3}.
x=\frac{9\times 3}{2\times 17}
Multiply \frac{9}{2} times \frac{3}{17} by multiplying numerator times numerator and denominator times denominator.
x=\frac{27}{34}
Do the multiplications in the fraction \frac{9\times 3}{2\times 17}.