Solve 5x+1/2y=135/11

$$5 x + \frac { 1 } { 2 } y = \frac { 135 } { 11 }$$

Solve for x

$$x=-\frac{y}{10}+\frac{27}{11}$$

Steps for Solving Linear Equation

Subtract \frac{1}{2}y from both sides.

$$5x=\frac{135}{11}-\frac{1}{2}y$$

The equation is in standard form.

$$5x=-\frac{y}{2}+\frac{135}{11}$$

Divide both sides by 5.

$$\frac{5x}{5}=\frac{-\frac{y}{2}+\frac{135}{11}}{5}$$

Dividing by 5 undoes the multiplication by 5.

$$x=\frac{-\frac{y}{2}+\frac{135}{11}}{5}$$

Divide \frac{135}{11}-\frac{y}{2} by 5.

$$x=-\frac{y}{10}+\frac{27}{11}$$

Solve for y

$$y=\frac{270}{11}-10x$$

Steps for Solving Linear Equation

Subtract 5x from both sides.

$$\frac{1}{2}y=\frac{135}{11}-5x$$

Multiply both sides by 2.

$$\frac{\frac{1}{2}y}{\frac{1}{2}}=\frac{\frac{135}{11}-5x}{\frac{1}{2}}$$

Dividing by \frac{1}{2} undoes the multiplication by \frac{1}{2}.

$$y=\frac{\frac{135}{11}-5x}{\frac{1}{2}}$$

Divide \frac{135}{11}-5x by \frac{1}{2} by multiplying \frac{135}{11}-5x by the reciprocal of \frac{1}{2}.

$$y=\frac{270}{11}-10x$$