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5u^{2}\left(u-1\right)+8\left(u-1\right)
Do the grouping 5u^{3}-5u^{2}+8u-8=\left(5u^{3}-5u^{2}\right)+\left(8u-8\right), and factor out 5u^{2} in the first and 8 in the second group.
\left(u-1\right)\left(5u^{2}+8\right)
Factor out common term u-1 by using distributive property. Polynomial 5u^{2}+8 is not factored since it does not have any rational roots.