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5t^{2}-1=0
Add -4 and 3 to get -1.
5t^{2}=1
Add 1 to both sides. Anything plus zero gives itself.
t^{2}=\frac{1}{5}
Divide both sides by 5.
t=\frac{\sqrt{5}}{5} t=-\frac{\sqrt{5}}{5}
Take the square root of both sides of the equation.
5t^{2}-1=0
Add -4 and 3 to get -1.
t=\frac{0±\sqrt{0^{2}-4\times 5\left(-1\right)}}{2\times 5}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 5 for a, 0 for b, and -1 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
t=\frac{0±\sqrt{-4\times 5\left(-1\right)}}{2\times 5}
Square 0.
t=\frac{0±\sqrt{-20\left(-1\right)}}{2\times 5}
Multiply -4 times 5.
t=\frac{0±\sqrt{20}}{2\times 5}
Multiply -20 times -1.
t=\frac{0±2\sqrt{5}}{2\times 5}
Take the square root of 20.
t=\frac{0±2\sqrt{5}}{10}
Multiply 2 times 5.
t=\frac{\sqrt{5}}{5}
Now solve the equation t=\frac{0±2\sqrt{5}}{10} when ± is plus.
t=-\frac{\sqrt{5}}{5}
Now solve the equation t=\frac{0±2\sqrt{5}}{10} when ± is minus.
t=\frac{\sqrt{5}}{5} t=-\frac{\sqrt{5}}{5}
The equation is now solved.