Solve for t
t>2
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5t-\frac{3}{2}t>7
Subtract \frac{3}{2}t from both sides.
\frac{7}{2}t>7
Combine 5t and -\frac{3}{2}t to get \frac{7}{2}t.
t>7\times \frac{2}{7}
Multiply both sides by \frac{2}{7}, the reciprocal of \frac{7}{2}. Since \frac{7}{2} is positive, the inequality direction remains the same.
t>2
Cancel out 7 and 7.
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