Solve 5m*(-9/4abm)*(-am)

$$5 m \cdot ( - \frac { 9 } { 4 } abm ) \cdot ( - am )$$

Evaluate

$$\frac{45ba^{2}m^{3}}{4}$$

Solution Steps

Multiply m and m to get m^{2}.

$$5m^{2}\left(-\frac{9}{4}\right)ab\left(-a\right)m$$

To multiply powers of the same base, add their exponents. Add 2 and 1 to get 3.

$$5m^{3}\left(-\frac{9}{4}\right)ab\left(-a\right)$$

Express 5\left(-\frac{9}{4}\right) as a single fraction.

$$\frac{5\left(-9\right)}{4}m^{3}ab\left(-a\right)$$

Multiply 5 and -9 to get -45.

$$\frac{-45}{4}m^{3}ab\left(-a\right)$$

Fraction \frac{-45}{4} can be rewritten as -\frac{45}{4} by extracting the negative sign.

$$-\frac{45}{4}m^{3}ab\left(-a\right)$$

Multiply -\frac{45}{4} and -1 to get \frac{45}{4}.

$$\frac{45}{4}m^{3}aba$$

Multiply a and a to get a^{2}.

$$\frac{45}{4}m^{3}a^{2}b$$

Differentiate w.r.t. b

$$\frac{45a^{2}m^{3}}{4}$$