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5t^{2}+13t-6=0
Substitute t for m^{2}.
t=\frac{-13±\sqrt{13^{2}-4\times 5\left(-6\right)}}{2\times 5}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Substitute 5 for a, 13 for b, and -6 for c in the quadratic formula.
t=\frac{-13±17}{10}
Do the calculations.
t=\frac{2}{5} t=-3
Solve the equation t=\frac{-13±17}{10} when ± is plus and when ± is minus.
m=\frac{\sqrt{10}}{5} m=-\frac{\sqrt{10}}{5}
Since m=t^{2}, the solutions are obtained by evaluating m=±\sqrt{t} for positive t.