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5\left(m^{3}+64\right)
Factor out 5.
\left(m+4\right)\left(m^{2}-4m+16\right)
Consider m^{3}+64. Rewrite m^{3}+64 as m^{3}+4^{3}. The sum of cubes can be factored using the rule: a^{3}+b^{3}=\left(a+b\right)\left(a^{2}-ab+b^{2}\right).
5\left(m+4\right)\left(m^{2}-4m+16\right)
Rewrite the complete factored expression. Polynomial m^{2}-4m+16 is not factored since it does not have any rational roots.