Skip to main content
Factor
Tick mark Image
Evaluate
Tick mark Image

Similar Problems from Web Search

Share

5\left(m^{3}+6m^{2}-7m\right)
Factor out 5.
m\left(m^{2}+6m-7\right)
Consider m^{3}+6m^{2}-7m. Factor out m.
a+b=6 ab=1\left(-7\right)=-7
Consider m^{2}+6m-7. Factor the expression by grouping. First, the expression needs to be rewritten as m^{2}+am+bm-7. To find a and b, set up a system to be solved.
a=-1 b=7
Since ab is negative, a and b have the opposite signs. Since a+b is positive, the positive number has greater absolute value than the negative. The only such pair is the system solution.
\left(m^{2}-m\right)+\left(7m-7\right)
Rewrite m^{2}+6m-7 as \left(m^{2}-m\right)+\left(7m-7\right).
m\left(m-1\right)+7\left(m-1\right)
Factor out m in the first and 7 in the second group.
\left(m-1\right)\left(m+7\right)
Factor out common term m-1 by using distributive property.
5m\left(m-1\right)\left(m+7\right)
Rewrite the complete factored expression.