Evaluate
10+35i
Real Part
10
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5i\times 7+5\left(-2\right)i^{2}
Multiply 5i times 7-2i.
5i\times 7+5\left(-2\right)\left(-1\right)
By definition, i^{2} is -1.
10+35i
Do the multiplications. Reorder the terms.
Re(5i\times 7+5\left(-2\right)i^{2})
Multiply 5i times 7-2i.
Re(5i\times 7+5\left(-2\right)\left(-1\right))
By definition, i^{2} is -1.
Re(10+35i)
Do the multiplications in 5i\times 7+5\left(-2\right)\left(-1\right). Reorder the terms.
10
The real part of 10+35i is 10.
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