Solve for f
f=\frac{1}{5}+\frac{2}{5x}
x\neq 0
Solve for x
x=\frac{2}{5f-1}
f\neq \frac{1}{5}
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5xf=x+2
The equation is in standard form.
\frac{5xf}{5x}=\frac{x+2}{5x}
Divide both sides by 5x.
f=\frac{x+2}{5x}
Dividing by 5x undoes the multiplication by 5x.
f=\frac{1}{5}+\frac{2}{5x}
Divide x+2 by 5x.
5fx-x=2
Subtract x from both sides.
\left(5f-1\right)x=2
Combine all terms containing x.
\frac{\left(5f-1\right)x}{5f-1}=\frac{2}{5f-1}
Divide both sides by 5f-1.
x=\frac{2}{5f-1}
Dividing by 5f-1 undoes the multiplication by 5f-1.
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