Solve 5f=2c-3/1-2k

$$5 f = \frac { 2 c - 3 } { 1 - 2 k }$$

Solve for c

$$c=-5fk+\frac{5f}{2}+\frac{3}{2}$$

$$k\neq \frac{1}{2}$$

Steps for Solving Linear Equation

Multiply both sides of the equation by -2k+1.

$$5f\left(-2k+1\right)=2c-3$$

Use the distributive property to multiply 5f by -2k+1.

$$-10fk+5f=2c-3$$

Swap sides so that all variable terms are on the left hand side.

$$2c-3=-10fk+5f$$

Add 3 to both sides.

$$2c=-10fk+5f+3$$

The equation is in standard form.

$$2c=3+5f-10fk$$

Divide both sides by 2.

$$\frac{2c}{2}=\frac{3+5f-10fk}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$c=\frac{3+5f-10fk}{2}$$

Divide -10fk+5f+3 by 2.

$$c=-5fk+\frac{5f}{2}+\frac{3}{2}$$

Solve for f

$$f=-\frac{3-2c}{5\left(1-2k\right)}$$

$$k\neq \frac{1}{2}$$

Steps for Solving Linear Equation

Multiply both sides of the equation by -2k+1.

$$5f\left(-2k+1\right)=2c-3$$

Use the distributive property to multiply 5f by -2k+1.

$$-10fk+5f=2c-3$$

Combine all terms containing f.

$$\left(-10k+5\right)f=2c-3$$

The equation is in standard form.

$$\left(5-10k\right)f=2c-3$$

Divide both sides by 5-10k.

$$\frac{\left(5-10k\right)f}{5-10k}=\frac{2c-3}{5-10k}$$

Dividing by 5-10k undoes the multiplication by 5-10k.

$$f=\frac{2c-3}{5-10k}$$

Divide 2c-3 by 5-10k.

$$f=\frac{2c-3}{5\left(1-2k\right)}$$