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d\left(5d+11\right)
Factor out d.
5d^{2}+11d=0
Quadratic polynomial can be factored using the transformation ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), where x_{1} and x_{2} are the solutions of the quadratic equation ax^{2}+bx+c=0.
d=\frac{-11±\sqrt{11^{2}}}{2\times 5}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
d=\frac{-11±11}{2\times 5}
Take the square root of 11^{2}.
d=\frac{-11±11}{10}
Multiply 2 times 5.
d=\frac{0}{10}
Now solve the equation d=\frac{-11±11}{10} when ± is plus. Add -11 to 11.
d=0
Divide 0 by 10.
d=-\frac{22}{10}
Now solve the equation d=\frac{-11±11}{10} when ± is minus. Subtract 11 from -11.
d=-\frac{11}{5}
Reduce the fraction \frac{-22}{10} to lowest terms by extracting and canceling out 2.
5d^{2}+11d=5d\left(d-\left(-\frac{11}{5}\right)\right)
Factor the original expression using ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Substitute 0 for x_{1} and -\frac{11}{5} for x_{2}.
5d^{2}+11d=5d\left(d+\frac{11}{5}\right)
Simplify all the expressions of the form p-\left(-q\right) to p+q.
5d^{2}+11d=5d\times \frac{5d+11}{5}
Add \frac{11}{5} to d by finding a common denominator and adding the numerators. Then reduce the fraction to lowest terms if possible.
5d^{2}+11d=d\left(5d+11\right)
Cancel out 5, the greatest common factor in 5 and 5.