Solve 5am+9^2b=k

$$5 a m + 9 ^ { 2 } b = k$$

Solve for a

$$\left\{\begin{matrix}a=-\frac{81b-k}{5m}\text{, }&m\neq 0\\a\in \mathrm{R}\text{, }&b=\frac{k}{81}\text{ and }m=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Calculate 9 to the power of 2 and get 81.

$$5am+81b=k$$

Subtract 81b from both sides.

$$5am=k-81b$$

The equation is in standard form.

$$5ma=k-81b$$

Divide both sides by 5m.

$$\frac{5ma}{5m}=\frac{k-81b}{5m}$$

Dividing by 5m undoes the multiplication by 5m.

$$a=\frac{k-81b}{5m}$$

Solve for b

$$b=\frac{k-5am}{81}$$

Steps for Solving Linear Equation

Calculate 9 to the power of 2 and get 81.

$$5am+81b=k$$

Subtract 5am from both sides.

$$81b=k-5am$$

Divide both sides by 81.

$$\frac{81b}{81}=\frac{k-5am}{81}$$

Dividing by 81 undoes the multiplication by 81.

$$b=\frac{k-5am}{81}$$