Solve for a
a=\frac{4\left(x+3b\right)}{15}
Solve for b
b=\frac{5a}{4}-\frac{x}{3}
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15a-3x=x+12b
Multiply both sides of the equation by 3.
15a=x+12b+3x
Add 3x to both sides.
15a=4x+12b
Combine x and 3x to get 4x.
\frac{15a}{15}=\frac{4x+12b}{15}
Divide both sides by 15.
a=\frac{4x+12b}{15}
Dividing by 15 undoes the multiplication by 15.
a=\frac{4b}{5}+\frac{4x}{15}
Divide 4x+12b by 15.
15a-3x=x+12b
Multiply both sides of the equation by 3.
x+12b=15a-3x
Swap sides so that all variable terms are on the left hand side.
12b=15a-3x-x
Subtract x from both sides.
12b=15a-4x
Combine -3x and -x to get -4x.
\frac{12b}{12}=\frac{15a-4x}{12}
Divide both sides by 12.
b=\frac{15a-4x}{12}
Dividing by 12 undoes the multiplication by 12.
b=\frac{5a}{4}-\frac{x}{3}
Divide 15a-4x by 12.
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