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Solve for a
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Solve for b
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5a=3b
Add 3b to both sides. Anything plus zero gives itself.
\frac{5a}{5}=\frac{3b}{5}
Divide both sides by 5.
a=\frac{3b}{5}
Dividing by 5 undoes the multiplication by 5.
-3b=-5a
Subtract 5a from both sides. Anything subtracted from zero gives its negation.
\frac{-3b}{-3}=-\frac{5a}{-3}
Divide both sides by -3.
b=-\frac{5a}{-3}
Dividing by -3 undoes the multiplication by -3.
b=\frac{5a}{3}
Divide -5a by -3.