Solve 5a+3+4a-2

$$5 a + 3 + 4 a - 2$$

Evaluate

$$9a+1$$

Solution Steps

Combine 5a and 4a to get 9a.

$$9a+3-2$$

Subtract 2 from 3 to get 1.

$$9a+1$$

Differentiate w.r.t. a

$$9$$

Steps Using Derivative Rule for Sum

Combine 5a and 4a to get 9a.

$$\frac{\mathrm{d}}{\mathrm{d}a}(9a+3-2)$$

Subtract 2 from 3 to get 1.

$$\frac{\mathrm{d}}{\mathrm{d}a}(9a+1)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$9a^{1-1}$$

Subtract 1 from 1.

$$9a^{0}$$

For any term t except 0, t^{0}=1.

$$9\times 1$$

For any term t, t\times 1=t and 1t=t.

$$9$$