Solve for a
a=\frac{2\left(6+c-b\right)}{5}
Solve for b
b=-\frac{5a}{2}+c+6
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5a-2c=12-2b
Subtract 2b from both sides.
5a=12-2b+2c
Add 2c to both sides.
5a=12+2c-2b
The equation is in standard form.
\frac{5a}{5}=\frac{12+2c-2b}{5}
Divide both sides by 5.
a=\frac{12+2c-2b}{5}
Dividing by 5 undoes the multiplication by 5.
2b-2c=12-5a
Subtract 5a from both sides.
2b=12-5a+2c
Add 2c to both sides.
2b=12+2c-5a
The equation is in standard form.
\frac{2b}{2}=\frac{12+2c-5a}{2}
Divide both sides by 2.
b=\frac{12+2c-5a}{2}
Dividing by 2 undoes the multiplication by 2.
b=-\frac{5a}{2}+c+6
Divide 12-5a+2c by 2.
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