Solve 5A=(B+b/2)h

$$5 A = ( \frac { B + b } { 2 } ) h$$

Solve for A

$$A=\frac{h\left(B+b\right)}{10}$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 2.

$$10A=\left(B+b\right)h$$

Use the distributive property to multiply B+b by h.

$$10A=Bh+bh$$

Divide both sides by 10.

$$\frac{10A}{10}=\frac{h\left(B+b\right)}{10}$$

Dividing by 10 undoes the multiplication by 10.

$$A=\frac{h\left(B+b\right)}{10}$$

Solve for B

$$\left\{\begin{matrix}B=-b+\frac{10A}{h}\text{, }&h\neq 0\\B\in \mathrm{R}\text{, }&A=0\text{ and }h=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 2.

$$10A=\left(B+b\right)h$$

Use the distributive property to multiply B+b by h.

$$10A=Bh+bh$$

Swap sides so that all variable terms are on the left hand side.

$$Bh+bh=10A$$

Subtract bh from both sides.

$$Bh=10A-bh$$

The equation is in standard form.

$$hB=10A-bh$$

Divide both sides by h.

$$\frac{hB}{h}=\frac{10A-bh}{h}$$

Dividing by h undoes the multiplication by h.

$$B=\frac{10A-bh}{h}$$

Divide 10A-bh by h.

$$B=-b+\frac{10A}{h}$$