Solve 5-px=qx-5

$$5 - p x = q x - 5$$

Solve for p

$$p=-q+\frac{10}{x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Subtract 5 from both sides.

$$-px=qx-5-5$$

Subtract 5 from -5 to get -10.

$$-px=qx-10$$

The equation is in standard form.

$$\left(-x\right)p=qx-10$$

Divide both sides by -x.

$$\frac{\left(-x\right)p}{-x}=\frac{qx-10}{-x}$$

Dividing by -x undoes the multiplication by -x.

$$p=\frac{qx-10}{-x}$$

Divide qx-10 by -x.

$$p=-q+\frac{10}{x}$$

Solve for q

$$q=-p+\frac{10}{x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$qx-5=5-px$$

Add 5 to both sides.

$$qx=5-px+5$$

Add 5 and 5 to get 10.

$$qx=10-px$$

The equation is in standard form.

$$xq=10-px$$

Divide both sides by x.

$$\frac{xq}{x}=\frac{10-px}{x}$$

Dividing by x undoes the multiplication by x.

$$q=\frac{10-px}{x}$$

Divide 10-px by x.

$$q=-p+\frac{10}{x}$$